Test 18 June for AM-JEE batch
Quiz Summary
0 of 7 Questions completed
Questions:
Information
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading…
You must sign in or sign up to start the quiz.
You must first complete the following:
Results
Results
0 of 7 Questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 point(s), (0)
Earned Point(s): 0 of 0, (0)
0 Essay(s) Pending (Possible Point(s): 0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- Current
- Review
- Answered
- Correct
- Incorrect
-
Question 1 of 7
1. Question
Prove that \(cos (A+B) = cos A. cosB – sin A. sin B\)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
-
Question 2 of 7
2. Question
Write the formulae for
- \(sin (A+B) = \)
- \(tan (A-B) = \)
- \(cos \ A – cos \ B =\)
- \(sin \ A – sin \ B =\)
- \(2cos \ A .Sin \ B = \)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
Question 3 of 7
3. Question
Prove that \(Cos \ A + Cos \ B = 2 cos \ {A+B \over 2} cos \ {A-B \over 2} \)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
-
Question 4 of 7
4. Question
\({sin \ (A+B) \over sin(A-B) } = {tan \ (A+B) \over tan(A-B) }\)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
-
Question 5 of 7
5. Question
\({tan \ 4 A }\) = \({4. tan \ A (1 – tan^2 A )} \over {1 – 6. tan^2A + tan^4A}\)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
-
Question 6 of 7
6. Question
Prove that \( sin \ A = sin \ B\) implies \(A = n \pi + (-1)^n B\), where \(n \ \epsilon \ Z\)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
-
Question 7 of 7
7. Question
Find solutions for \(x\) if \(cos \ x = {-1 \over 2}\) and \( -2 \pi \ < \ x \ < 2 \pi\)
-
This response will be reviewed and graded after submission.
Grading can be reviewed and adjusted.Grading can be reviewed and adjusted. -
